Lakshya Institute JEE Main 2026 Results
Gurugram’s Emerging Academic Excellence Hub
30+
Students Appeared
15+
80+ Percentile
8
Qualified for JEE Advanced
50%
Above National Cutoff
Featured Achievers

Mayank
85%ile – Gen EWS
Acquire Strong Problem solving skill

Kunal
80%ile – SC Category
Strong Internal Performer
Admissions Open for JEE 2027
Structured Strategy | Monthly Testing | Mentorship
Outstanding Success in JEE Main
Consistent 80+ | 90+ | 97+ Percentile Achievers from Gurugram

Next Success Story Could Be Yours.
Book Counselling for JEE 2027JEE Main 2026 Session 1 – Results Summary & Analysis
The National Testing Agency (NTA) declared the JEE Main 2026 Session 1 results on February 16, 2026. Approximately 13.04 lakh candidates appeared this year, with 12 students achieving a perfect 100 percentile. The competition has intensified significantly compared to the previous year.
1. Comparison with Previous Year (2025 vs 2026)
| Parameter | JEE Main 2025 | JEE Main 2026 |
|---|---|---|
| Total Candidates Appeared | ~11.7 Lakh | ~13.04 Lakh |
| 100 Percentilers | 23 | 12 |
| Female Participation | ~4.0 Lakh | 4.49 Lakh |
| General Cutoff (Expected) | 93.23 | 93.5 – 94.1 |
| Difficulty Level | Moderate | Moderate to Difficult |
Key Insight: The 99th percentile required approximately 10–15 additional marks compared to 2025, reflecting tighter competition and a larger candidate pool.
2. Must-Remember High-Yield Formulas (Session 2)
Physics:
Coulomb’s Law: F = k(q₁q₂)/r²
Drift Velocity: v = eEτ/m = I/(neA)
Projectile Range: R = u² sin2θ / g
Coulomb’s Law: F = k(q₁q₂)/r²
Drift Velocity: v = eEτ/m = I/(neA)
Projectile Range: R = u² sin2θ / g
Chemistry:
Nernst Equation: E = E° − (0.0591/n) logQ
First Order Decay: k = (2.303/t) log(A₀/At)
Magnetic Moment: μ = √n(n+2)
Nernst Equation: E = E° − (0.0591/n) logQ
First Order Decay: k = (2.303/t) log(A₀/At)
Magnetic Moment: μ = √n(n+2)
Mathematics:
Euler’s Form: e^(iθ) = cosθ + isinθ
Integration by Parts Formula
Distance (Point to Line): |ax₁ + by₁ + c| / √(a² + b²)
Euler’s Form: e^(iθ) = cosθ + isinθ
Integration by Parts Formula
Distance (Point to Line): |ax₁ + by₁ + c| / √(a² + b²)
3. Frequently Asked Questions (FAQs)
Q1: Can I improve significantly in Session 2?
Yes. Nearly 30% of students improve in Session 2. Focus on gap analysis, weak chapters, and reducing silly mistakes.
Q2: Will JEE Advanced cutoff increase?
Yes, due to increased participation (13+ lakh candidates), the General category qualifying percentile is expected between 93.5 and 94.2.
Q3: Does NTA consider the best of two sessions?
Yes. The better percentile of Session 1 and Session 2 will be used for AIR calculation.
